Question

in triangle ABC AB=AC angle A=80 then the measure of angle b and angle c are? ​

Answer 1

Answer:

Angle B and Angle C = 50°

Step-by-step explanation:

In the triangle ABC, Arm AB=AC which means it is an isosceles triangle. Taking the property of isosceles, i.e. The angles situated opposite to the equal sides of an isosceles triangle are always equal; we get that angle b = angle c

Now a/q

80°+angle b + angle c = 180° (angle sum property)

80°+ 2(angle b) = 180° (angle b = angle c)

2(angle b) = 180°-80°

angle b = 100°/2

angle b = 50°

And as angle b = angle c; angle c = 50°

Answer 2

Answer:

Step-by-step explanation:

Angle B and Angle C = 50°

Step-by-step explanation:

In the triangle ABC, Arm AB=AC which means it is an isosceles triangle. Taking the property of isosceles, i.e. The angles situated opposite to the equal sides of an isosceles triangle are always equal; we get that angle b = angle c

Now a/q

80°+angle b + angle c = 180° (angle sum property)

80°+ 2(angle b) = 180° (angle b = angle c)

2(angle b) = 180°-80°

angle b = 100°/2

angle b = 50°

And as angle b = angle c; angle c = 50°