in triangle ABC, AB = AC if angle DAB = 70° and DA || BC find angle BAC
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Answer:
40 degree
Step-by-step explanation:
in this angle DAB = angle ABC = 70 degree (alternate interior angles are equal)
angle ABC = angle ACB = 70 degree (since AB = AC, angle opposite to equal sides are also equal)
therefore in triangle ABC,
angle ABC=70 Degree
angle ACB=70 Degree
so angle BAC= 40 degree (sum of all angles in a triangle is 180 degree, therefore angle BAC=(180-(70+70))=(180-140)=40 degree.
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