Math, asked by maniksharma2993, 5 months ago

In Triangle ABC, AB = Ac. The
bisectors of angle B and angles C intersect at . Join A to O. Prove
angle PQS = angle PRT​

Answers

Answered by Anonymous
0

Answer:

ANSWER

Since the angles opposite to equal sides are equal,

∴AB=AC

⇒∠C=∠B

2

∠B

=

2

∠C

.

Since BO and CO are bisectors of ∠B and ∠C, we also have

∠ABO=

2

∠B

and ∠ACO=

2

∠C

.

∠ABO=

2

∠B

=

2

∠C

=∠ACO.

Consider △BCO:

∠OBC=∠OCB

⇒BO=CO ....... [Sides opposite to equal angles are equal]

Finally, consider triangles ABO and ACO.

BA=CA ...... (given);

BO=CO ...... (proved);

∠ABO=∠ACO (proved).

Hence, by S.A.S postulate

△ABO≅△ACO

⇒∠BAO=∠CAO⇒AO bisects ∠A.

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