In triangle ABC, AC=10 cm, angle ACB=60° and AD perpendicular to BC. If BD= 15 cm , then find the measure of angle B
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Answer:
Answer below
Step-by-step explanation:
Given:
∠ABC=90
o
,BD⊥AC,
BD=8 and AD=4 as in diagram.
Let ∠ACB=x
⇒∠CBD=90−x
⇒∠ABD=x
⇒∠BAD=90−x
⇒ΔABC,ΔADB and ΔBDC are similar
⇒
CD
BD
=
DB
AD
⇒
CD
8
=
8
4
⇒CD=
4
8×8
=16cm.
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