In triangle ABC , AD BC , AC =50cm , BD =9cm , DC = 30cm . Find a)AD b)area of triangle ABC. c)perimeter of triangle ABC
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Step-by-step explanation:
a) AD : To find AD, we consider the triangle ADC, since angle D is perpendicular i.e., 90 degree, we use the Pythagoras theorem.
AD^2 = 50*50 - 30*30 = 2500 - 900 = 1600
AD = 40cm
b) Area = 1/2(b*h) = 40*39 / 2 = 39 *20 = 780cm^2
c) Perimeter = sum of the sides = 50+39+AB
By Pythagoras theorem, AB^2 = 1600+81 = 1681 , AB = 41
Perimeter = sum of the sides = 50+39+41 = 130
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