Question

In triangle ABC , AD is a median. X is a point on AD such that AX : XD = 2:3. Ray BX intersect AC in Y. Prove that AC:AY=4:1​

Answer 1

Answer:

AD is a median of triangle ABC and E is the midpoint of AD. BE produced meets AC in F, Prove that AF 1/3 AC

Q2

In a triangle ABC,AD is a median and E is mid-point of median AD. A line through B and E meets AC at point F.

Prove that: AC=3AF

Q3

In a triangle ABC median AD is produced to X such that AD+DX. Prove that ABXC is a parallelogram.