Question

In Triangle ABC, AD is an altitude and A is right angle. If AB = √20 , BD = 4 then find CD

Answer 1

Answer: this question is wrong instead of altitude there should be median so if it is median then CD=4cm

Step-by-step explanation:

Answer 2

The length of CD is 1

Explanation:

Given that ABC is a triangle.

AD is an altitude and A is the right angle.

It is also given that $A B=\sqrt{20}$ and $\ {BD}=4$

We need to find the length of CD

Using similar right triangles theorem, "if an altitude is drawn to hypotenuse of a right angled triangle, then the length of each side other than the hypotenuse is the geometric mean of length of hypotenuse and segment of hypotenuse adjacent to the side".

Thus, we have,

$A B^{2}=B D \cdot B C$

Substituting the values, we have,

$(\sqrt{20})^2=4(BC)$

      $20=4 ({BC})$

        $5=BC$

The length of CD can be determined by subtracting BC and BD

Thus, we have,

$\ {CD}=\ {BC}-\ {BD}$

$C D=5-4$

$\ {CD}=1$

Thus, the length of CD is 1

Learn more:

(1) In Triangle ABC, AD is an altitude and A is right angle. If AB = √20 , BD = 4 then find CD​

brainly.in/question/15094127

(2) In ∆ABC,AD is in altitude and angle A is right angle . if AB=√20,BD=4 then find CD

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