Question

In triangle ABC, ad is an angle bac divisor if ab = 6 cm ac = 5 cm and bd = 3 cm then dc =?​

Answer 1

Answer:

By Angle bisector theorem: which states that, the ratio of any 2 sides of a triangle is equal to the ratio of the lengths of the segments formed on its third side, by the angle bisector of the angle formed by those 2 sides.

So, here, AB/AC = BD/DC

=> 6/5 = 3 / DC

=> DC = 15/6 = 5/2 = 2.5 cm

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Answer 2

Answer:

2.5 cm

Step-by-step explanation:

Let the given ∆ABC be as a triangle

Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DC where, BC=3cm . We also have the values of adjacent sides AB=6cm and AC=5cm .

Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DC where, BC=3cm . We also have the values of adjacent sides AB=6cm and AC=5cm .These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:

Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DC where, BC=3cm . We also have the values of adjacent sides AB=6cm and AC=5cm .These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:ABBD=ACDC

Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DC where, BC=3cm . We also have the values of adjacent sides AB=6cm and AC=5cm .These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:ABBD=ACDC ⇒DC=AC∗BDAB=5∗36=2.5cm