Question

In triangle ABC , AD is the internal bisector of angle A , meeting the side BC at D . If BD =5 cm , BC=7.5cm then AB:AC is:?

Answer 1

Hey there,

In ∆ABC ,if AD is angle bisector of angle A,

Then ,AB:AC=BD:DC (by internal angle bisector theorem)

Then ,BD=5cm ,BC=7:5 cm

=>DC=7.5-5=2.5

AB:AC=BD:DC=5:2.5=2:1

Hope it helps

Answer 2

Answer:

Step-by-step explanation:

It is given that In triangle ABC , AD is the internal bisector of angle A , meeting the side BC at D , BD =5 cm , BC=7.5cm.

Now, DC=BC-BD, therefore

DC=7.5-5=2.5

Since, AD is the internal bisector of the angle A, therefore using the angle bisector theorem in ΔABC, we have

$\frac{AB}{AC}=\frac{BD}{DC}$

$\frac{AB}{AC}=\frac{5}{2.5}$

$\frac{AB}{AC}=\frac{2}{1}$

Thus, AB:AC=2:1