Question

In triangle ABC,AD parallel to BC .Bc=12cm area of triangle ABC =30cm square. find AD​

Answer 1

Answer:

In triangle ABC, <BCA = 60 and <ABC = 30

So < BAC = 180 - 60 - 30. = 90… sum of angles of triangle is 180°

sin<ABC = AC/BC

sin 30 = AC/12

0.5 = AC/12

AC = 6 cm

Now, in triangle ADC,

sin<ACD = AD/AC

sin 60 = AD/6

√3/2 = AD/6

AD = 6√3/2 =3√3 cm