in triangle ABC. AD perpendicular to BC and AD^2 = BD× DC prove that angle BAC is equal to 90 degree
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ONKAR2003:
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in which class u r
10th
only one year old
so late replying
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in triangle abc ,bd×dc=ad^2
d=90°,hence dab and dac are right angle triangles
according to pythogarus triplet
ad^2+db^2=ab^2-------(1)
ad^2+dc^2=ac^2-------(2)
add (1)+(2)
ab^2+ac^2=2ad^2 +db^2+dc^2
we know that bd×dc=ad^2
ab^2+ac^2=bc^2
hence a=90°
d=90°,hence dab and dac are right angle triangles
according to pythogarus triplet
ad^2+db^2=ab^2-------(1)
ad^2+dc^2=ac^2-------(2)
add (1)+(2)
ab^2+ac^2=2ad^2 +db^2+dc^2
we know that bd×dc=ad^2
ab^2+ac^2=bc^2
hence a=90°
please.....if anyone can answer my questions ,please answer
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