Question

In triangle ABC,AE is external bisector of angle A meeting BC produced at E.If AB=10cm,AC=6cm and BC=12cm,then find CE

Answer 1

u can add this
10+6+12=16+12=28
the answer CE =28
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Answer 2

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[HERE YOUR ANSWER]



Given : AB = 10 cm, AC = 6 cm and BC = 12 cm

[By exterior angle bisector theorem ]
USE

BE / CE = AB / AC

(12 + x) / x = 10 / 6

6( 12 + x ) = 10 x [ by crossmultiplication]

B72 + 6x = 10x
= 10x – 6x

= 72 = 4x

x = 72/4

x = 18

CE is = 18 cm


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