(x+1) (2x+8) = (x+7) (x+3) quadratic equations using factorisation method
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Hola there,
Given
=> (x + 1)(2x + 8) = (x + 7)(x + 3)
=> 2x² + 8x + 2x + 8 = x² + 3x + 7x + 21
=> 2x² - x² + 10x - 10x + 8 - 21 = 0
=> x² - 13 = 0
Hope this helps...:)
Given
=> (x + 1)(2x + 8) = (x + 7)(x + 3)
=> 2x² + 8x + 2x + 8 = x² + 3x + 7x + 21
=> 2x² - x² + 10x - 10x + 8 - 21 = 0
=> x² - 13 = 0
Hope this helps...:)
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