In triangle ABC Al and cm are perpendicular to BC and ab respectively, cl=Al=2bl, then find MC/am
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Given : BL is perpendicular to AC and MC is perpendicular to LN. AL=CN and BL=CM
In ΔABL and ΔNMC
AL=CN
∠ALB=∠NCM=
BL=CM
Therefore ΔABLΔNMC (by SAS rule)
AB=NM ( CPCT)
∠BAL=∠MNC (CPCT)
AL=CN ⇒ AL+LC=LC+CN⇒AC=LN
Now in ΔABC and ΔNML
AB=NM
∠BAC=∠MNL
AC=LN
Therefore ΔABCΔNML (by SAS rule)
In ΔABL and ΔNMC
AL=CN
∠ALB=∠NCM=
BL=CM
Therefore ΔABLΔNMC (by SAS rule)
AB=NM ( CPCT)
∠BAL=∠MNC (CPCT)
AL=CN ⇒ AL+LC=LC+CN⇒AC=LN
Now in ΔABC and ΔNML
AB=NM
∠BAC=∠MNL
AC=LN
Therefore ΔABCΔNML (by SAS rule)
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