Question

solve: ¡)3(n-5)=21
¡¡)4+3(t+2)=16
​

Answer 1

$Given \: 3(n-5) = 21$

/* Dividing bothsides by 3 , we get */

$\implies \frac{3(n-5)}{3} = \frac{21}{3}$

$\implies n-5 = 7$

$\implies n = 7+5$

$\implies n = 12$

Therefore.,

$\red{ Value \: of \: n }\green { = 12}$

$ii) Given \: 4+3(t+2)= 16$

$\implies 3(t+2) = 16 - 4$

$\implies 3(t+2) = 12$

$\implies t +2 = \frac{12}{3}$

$\implies t + 2 = 4$

$\implies t = 4 - 2$

$\implies t = 2$

Therefore.,

$\red{ Value \: of \: t }\green { = 2 }$

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Answer 2

Answer :

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