in triangle ABC, altutude AD bisects BC. prove that triangle ADB congruent to triangle ADC. Write aqual pair of sides of the 2 triangles
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Given that : AD perpendicular to BC
To prove that : triangle ADB congruent to triangle ADC
We have,
BD = CD (BC bisected by AD)
Angle ADB = Angle ADC=90°
AD (common side)
Therefore, ∆ADB congruent to ∆ADB
(by SAS)
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