Question

In triangle ABC & PQR, & triangle ABC ~ triangle PQR, if & AB = PQ = 1:3, find ar(PQR) : ar(ABC). Please answer it with explanation.... ​

Answer 1

ABC ~ PQR

$\frac{ar(abc)}{ar(pqr)} = \ { (\frac{ab}{pq}) }^{2} \\ and \: \: \frac{ar(pqr)}{ar(abc)} = { { (\frac{pq}{ab} )} }^{2}$

$\frac{ar(pqr)}{ar(abc)} = { (\frac{3}{1}) }^{2} = \frac{9}{1}(ans).$

HOPE IT IS HELPFUL. ☺