In triangle ABC angle A= 2 angle C. Show that c(b+c)=a².
haindavi:
u r right but in the question they did not gave total information
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In a triangle : angle A =2 * angle C
so angle B = 180 deg - 2 angle C - angle C
B = 180 - 3 C
we know that
Sin 2C = 2 Sin C Cos C
Sin 3C = 3 Sin C - 4 Sin³ C = Sin C [ 3 - 4 Sin² C ] = Sin C [ 2 Cos 2C + 1 ]
we know that: a / Sin A = b / Sin B = c / Sin C
=> a / Sin 2C = b / Sin 3C = c / Sin C
=> a = 2 c Cos C -- (1)
and b = c {1 + 2 Cos 2C ] --- (2)
Now find a² - c² = 4 c² Cos² C - c²
= c² [ 4 Cos² C - 1 ]
= c² [ 2 Cos 2C + 1 ]
substitute from (2),
a² - c² =c² * b/c = bc
=> a² = c (b+c)
proved.
so angle B = 180 deg - 2 angle C - angle C
B = 180 - 3 C
we know that
Sin 2C = 2 Sin C Cos C
Sin 3C = 3 Sin C - 4 Sin³ C = Sin C [ 3 - 4 Sin² C ] = Sin C [ 2 Cos 2C + 1 ]
we know that: a / Sin A = b / Sin B = c / Sin C
=> a / Sin 2C = b / Sin 3C = c / Sin C
=> a = 2 c Cos C -- (1)
and b = c {1 + 2 Cos 2C ] --- (2)
Now find a² - c² = 4 c² Cos² C - c²
= c² [ 4 Cos² C - 1 ]
= c² [ 2 Cos 2C + 1 ]
substitute from (2),
a² - c² =c² * b/c = bc
=> a² = c (b+c)
proved.
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