Question

In triangle ABC angle A=30 BC²=4m(10-3√3) and AC:AB= 1:3 if the square of the area of triangle ABC=p/q where GCD(p, q)=1 then find p+q​

Answer 1

Answer:

By Pythagoras Theorem,

⇒ AC2 = AB2+ BC2

Given in ΔABC, AB = 3, BC = 4, AC = 5.

⇒ 52 = 32 + 42

⇒ 25 = 25

∴ ΔABC is a right angled triangle and ∠B is a right angle.

We know that the radius of the circle touching all the sides is (AB + BC – AC )/ 2

⇒ The required radius of circle = (3 + 4 – 5 )/2 = 2/2 = 1

Step-by-step explanation:

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