In triangle ABC, angle A=54°, angle C=96°, and AC=275. Find angle B, AB, and BC.
Use the law of sines
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Answer:
If AB = AC
⇒ This is an isosceles triangle
⇒ Two of the angles are equal
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∠a = 44 (Given)
Sum of angles in a triangle is equal to 180°
∠a + ∠b + ∠c = 180
44 + ∠b + ∠c = 180
∠b + ∠c = 136
Since ∠b and ∠c are equal:
∠b = ∠c = 136 ÷ 2 = 68°
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Answer ∠b = 68° and ∠c = 68
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