Question

in triangle ABC angle A =60° ,angle C =40° and bisector of triangle ABC meets sides AC at point P. Show that BP =CP​

Answer 1

Answer:

I think so it is 80 and mark me as brainliest

Answer 2

${\huge{\bf\blue{hy\:mate}}}$

angle A =60°,angleC=40°so angleB=80°

the bisector of angleABC is equal to 40°

since here, angle PBC =anglePCB

therefore by using property that if in a triangle two angles are equal then there corresponding lines are also equal

so, BP=CP.

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