In triangle ABC angle A =90°,AB =5cm and AC=12 cm. If AD perpendicular TO BCthen find AD
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area of triangle = (1/2) × base×height
if we take AC as perpendicular then AB will be base.
then area of triangle = (1/2)× 5×12 = 30 cm²
also, by Pythagoras' theorem,
BC² = AC² +AB²
=12² + 5² = 169
⇒BC = 13 cm
now, if AD is perpendicular then BC is the base
area of triangle = (1/2)× BC ×AD
⇒30 = (1/2)× 13×AD
⇒AD = 60/13 =4.61 cm
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if we take AC as perpendicular then AB will be base.
then area of triangle = (1/2)× 5×12 = 30 cm²
also, by Pythagoras' theorem,
BC² = AC² +AB²
=12² + 5² = 169
⇒BC = 13 cm
now, if AD is perpendicular then BC is the base
area of triangle = (1/2)× BC ×AD
⇒30 = (1/2)× 13×AD
⇒AD = 60/13 =4.61 cm
please mark me as brainliest
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