In triangle ABC;angle a=90°, sideAB= x cm, AC= (x+5)cm and area = 150 square metre. Find the sides of the triangle
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Given that angle A is 90°
So AB = height = x cm
AC = base = x+5 cm
Area = 150 cm^2
it is wrong
=> 1/2 × base × height = 150
=> 1/2 × (x+5) × x = 150
=> x(x+5) = 2×150 =300
=> x^2 + 5x - 300 = 0
=> x^2 + 20x -15x - 300 = 0
=> x(x+20) - 15(x+20) = 0
=> (x+20)(x-15)= 0
=> x = 15 or -20
Since length can not be negative, x = 15 cm
height = x = 15cm
base = x+5 = 15+5 = 20 cm
hypotenuse = √(15^2 + 20^2) = √625 = 25cm
Sides of triangle are 15cm, 20cm and 25cm.
Answered by
27
Given that angle A is 90°
So AB = height = x cm
AC = base = x+5 cm
Area = 150 cm^2
(you have wrongly mentioned it as m^2)
=> 1/2 × base × height = 150
=> 1/2 × (x+5) × x = 150
=> x(x+5) = 2×150 =300
=> x^2 + 5x - 300 = 0
=> x^2 + 20x -15x - 300 = 0
=> x(x+20) - 15(x+20) = 0
=> (x+20)(x-15)= 0
=> x = 15 or -20
Since length can not be negative, x = 15 cm
height = x = 15cm
base = x+5 = 15+5 = 20 cm
hypotenuse = √(15^2 + 20^2) = √625 = 25cm
Sides of triangle are 15cm, 20cm and 25cm.
So AB = height = x cm
AC = base = x+5 cm
Area = 150 cm^2
(you have wrongly mentioned it as m^2)
=> 1/2 × base × height = 150
=> 1/2 × (x+5) × x = 150
=> x(x+5) = 2×150 =300
=> x^2 + 5x - 300 = 0
=> x^2 + 20x -15x - 300 = 0
=> x(x+20) - 15(x+20) = 0
=> (x+20)(x-15)= 0
=> x = 15 or -20
Since length can not be negative, x = 15 cm
height = x = 15cm
base = x+5 = 15+5 = 20 cm
hypotenuse = √(15^2 + 20^2) = √625 = 25cm
Sides of triangle are 15cm, 20cm and 25cm.
TPS:
no problem:)
I did not understand that how 15x and 20x is coming
there is 15x or 20x
thanks Sona
there is no 15x or 20x
x =15, which came by solving the equation.
Can u show me the equation
I sincerely request you to go through my answer atleast once thoroughly before posting your doubts. Thank you
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