in triangle abc angle A equal to 45 degree and angle b equal to 25 degree find the exterior angle of b
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Step-by-step explanation:
∠A = 45°
∠B = 25°
∠C + ∠A + ∠B = 180° (Angle sum property)
∠C + 45° + 25° = 180°
∠C + 70°= 180°
∠C = 180° - 70°
∠C = 110°
Let exterior angle of ∠B be ∠D.
∠D = ∠A + ∠C (Exterior angle property)
∠D = 45° + 110°
∠D = 155°
ANSWER: Exterior angle of ∠B is equal to 155°
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