Question

In triangle ABC, angle a= x° , angle b=3x° , angle c= y°. If 3y-3x=30,find the angles of the triangle.​

Answer 1

Step-by-step explanation:

Using angle sum property,

angle a +angle b+ angle c =180

x+3x+y=180

4x+y=180(equation 1)

Given 3y-3x=30

-3x+3y=30

3x-3y=-30

x-y=-10(equation 2)

Now adding equation 1 and 2

x-y+4x+y=180-10

5x=170

x=34

Now puttion x=38 in equation 2

34-y=-10

y=44

hence Angle A=34°

Angle B=3×34=102°

Angle C=44°

Answer 2

Step-by-step explanation:

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