in triangle ABC angle ABC=59 degree,angle ACB=41degree .find angle BAC
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angle BAC = 180 - angle ABC + angle ACB (angle sum property)
angle BAC = 180 - 59 + 41
angle BAC = 180 - 100
angle BAC = 80 degree
angle BAC = 180 - 59 + 41
angle BAC = 180 - 100
angle BAC = 80 degree
umairkamran1234:
Maharashtra
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HEYA ^_^
ANSWER ⤵⤵
⏩ In a triangle sum of all angles are equal to 180°.
ABC+ACB+BAC = 180°
59°+ 41°+ BAC = 180°
100° + BAC = 180°
BAC = 180° - 100°
BAC = 80°
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