Math, asked by r9409321584, 4 months ago

in triangle ABC angle ACD is exterior angle. if angle A:angle B= 6:4 and angle ACD=100. find angle A and B

Answers

Answered by 123UDAY123

1

Answer:

/_ACD + /_ACB = 180

100 + /_ACB = 180

/_ACB = 80

angle A + B+ C = 180

6x + 4x +80 = 180

10x = 180 - 80

x = 100/10

x = 10

angle A = 6x = 60

angle B = 4x = 40

angle C = 80

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