in triangle ABC, angle B = 35, C=55. prove that AC² = AB² + BC²
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In triangle abc angle b=35 angle c=55
Angle a+angle b+angle c=180
Angle a=90
By Pythagoras therom
Bc*2=ac*2+ab*2
Angle a+angle b+angle c=180
Angle a=90
By Pythagoras therom
Bc*2=ac*2+ab*2
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