Question

In triangle ABC angle B =90' AB=5cm and ac=12cm than determining sinA, secA, sinC and sec C. ​

Answer 1

Answer:

Aria of triangle=1/2,×hight×bases

given,∆ABC,angle A=90° ,AB=5cm,AC=12cm,AD=?

We know that,BC^=AB^+AC^

=5^+12^

=169cm^=13cm

There fore,ar(∆ABC)=1/2×AC×AB

=1/2×5×12cm^

=(5×6)cm^=30cm^

Sins,ar(∆ABC)=1/2×BC×AD

= 30 =13/2×AD

=AD=60/13cm

Answer 2

Answer:

AD = 30/16 cm calculate the sum u will get answer