Question

In triangle abc angle(b) =90 , d is any point on ab and de is perpendicular to ac . if ac=25cm, bc=20cm, de=4cm find ad

Answer 1

⇒CD=8×8 4 =16
⇒8 CD =4 8
⇒BD CD =AD DB
⇒∠ABD=x,⇒∠BAD=90−x
⇒ΔABC,ΔADB,andΔBDC
is perpendicular to
Given
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∠ABC=90∘,BD
BD=8,andAD=4
∠ACB=x,⇒∠CBD=90−x
, as shown in the diagram.
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