Question

in triangle ABC ,angle B=90 degree cosec A *cos C -sin A*sec C

Answer 1

Since it is a right angled triangle SinA=Cos C and Cosec A=Sec C

Which means Cosec A Cos C - Sin A SecC=0

Answer 2

Answer:

cosec(90-C) *cos C-sin(90-C)*sec C

sec C* cos C -cos C*sec C

sec C 1/sec C - cos C*1/cos C

1-1

=0

Step-by-step explanation:

A+B+C=180

A+90+C=180

A+C=180-90

A+C=90