Math, asked by paul79, 11 months ago

In triangle ABC, angle B = 90°, AB = 7 cm and AC - BC = 1 cm. Find the values of sin C and cos C.​

Answers

Answered by Loggie
10

Step-by-step explanation:

AB^2+BC^2 =AC^2

OR, AC^2 - BC^2 = AB^2

OR, (AC+BC)(AC-BC) = 7^2

OR, (AC+BC)× 1 = 49

OR, AC + BC = 49

AND, AC - BC = 1

SO, AC = 25 AND BC= 24

NOW,

sin C = 7/25

and, cosC = 24/25

it's the solution

Answered by Anonymous
2

Answer:

please find the answer in the attachment below

ATTACHMENT:

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