In triangle ABC , angle B=90°, AC= 12 cm, BC= 6cm . Find the measure of angle A
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Its a right angled triangle
So, angle A + angle C = 90°
So we use Pythagorean theorem where
AC² = AB² + BC²
(12)² = (6)² + BC²
BC² = 108
BC = √108 = 6√3
sinA = 6√3/12
sinA = √3/2 and sin60° = √3/2
So angle A = 60°
angle A = 60°angle C = 90° - 60°
angle A = 60°angle C = 90° - 60° angle C = 30°
So, angle A + angle C = 90°
So we use Pythagorean theorem where
AC² = AB² + BC²
(12)² = (6)² + BC²
BC² = 108
BC = √108 = 6√3
sinA = 6√3/12
sinA = √3/2 and sin60° = √3/2
So angle A = 60°
angle A = 60°angle C = 90° - 60°
angle A = 60°angle C = 90° - 60° angle C = 30°
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