Question

in triangle abc , angle b equal to 2 angle c and the bisector of angle abc intersect at the point p. prove that AB × BC = BP × CA.​

Answer 1

Answer:

$angle \: b = \: 2c + bisector \: of \: triangle \: abc \: \\ = b = 2c + 1 \div 2 \\ = so \: let \: us \: take \: angle \: c \: as \: x \: so \: 2c = 2x + 1 \div 2 \: then \: the \:$

Answer 2

Answer:

The Answer is Here

Step-by-step explanation:

Let angle C=45 so Ang.B=90 so let's assume it's a right angle Triangle.

so you can check the image.