Question

In triangle abc, angle b equal to 90 degree, bd perpendicular to ac. Prove that triangle adb similar to triangle bdc

Answer 1

given = tri Abc , B=90 & bd perpendicular to ac to prove = tri Abc ~ tri bdc
proof = an Bad=an cdb ( each 90 ) an abd=an cbd (comnan angle) so ,tri Abc~ Bdc from AA congruence