In triangle ABC angle b is 90 degrees, sin A =15/25 then find cos A, sinC, sin B and cos B.
Answers
Answered by
2
Answer:
cosA = 20/25
sinC =20/25
sinB =1
cosB =0
Answered by
1
Answer:
sinC = 20/25 , CosA = 20/25 ,sin b = , cosa =
Step-by-step explanation:
Given:- Sin A = 15/25
Sin= opp/hypotenuse
15/25 = AB/BC
Using Pythagoras theorem
A² + B²= C²
25²+ 15² = C²
50+30=C²
80=C²
√80 = C
4/5 = C
Cos A = adj / hypotenuse = 4/5 = 20/25
Sin C = 4/5 = 20/25
sinC = 20/25 , CosA = 20/25 ,sin b = , cosa =
Step-by-step explanation:
Given:- Sin A = 15/25
Sin= opp/hypotenuse
15/25 = AB/BC
Using Pythagoras theorem
A² + B²= C²
25²+ 15² = C²
50+30=C²
80=C²
√80 = C
4/5 = C
Cos A = adj / hypotenuse = 4/5 = 20/25
Sin C = 4/5 = 20/25
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