Math, asked by taiba4943, 11 months ago

In triangle abc angle bac is equal to 68degrees and angle abc is equal to 30degrees. bc is produced to x. the bisectors of angle abc and angle acx meet at p. calculate angle bcp and angle bpc.

Answers

Answered by vaishalikirang29
2

Answer:

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Answered by shaistha672
3

Step-by-step explanation:

given:<BAC=68°

<ABC=30

<ABC+<BAC+<ACB=180

30+68+<ACB=180

98+<ACB=180

<ACB=180-98

<ACB=82

<ACX=<BAC+<ABC(exterior angle

<ACX=68+30

<ACX=98

<BCP=<ACP+<ABC

<BCP=<ACX/2+82

<BCP=98/2+82

<BCP=49+82

<BCP=131

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