In triangle abc angle bac is equal to 68degrees and angle abc is equal to 30degrees. bc is produced to x. the bisectors of angle abc and angle acx meet at p. calculate angle bcp and angle bpc.
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Step-by-step explanation:
given:<BAC=68°
<ABC=30
<ABC+<BAC+<ACB=180
30+68+<ACB=180
98+<ACB=180
<ACB=180-98
<ACB=82
<ACX=<BAC+<ABC(exterior angle
<ACX=68+30
<ACX=98
<BCP=<ACP+<ABC
<BCP=<ACX/2+82
<BCP=98/2+82
<BCP=49+82
<BCP=131
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