Question

In triangle ABC angle C = 3,angle B=2(angleA + angle B) find all 3 angels of the triangle

Answer 1

Answer:

let <C=3<B=2<(A+B)=x

<C=x, -----(1)

3<B=x

<B=x/3----(2)

2<(A+B)=x

<A+<B=x/2

<A=x/2 -<B

<A=x/2-x/3-----(3)

sum of the three angles in a triangle is 180degree

<A+<B+<C=180

x/2-x/3+x/3+x=180[from(1),(2),(3)]

(3x-2x+2x+6x)/6=180

9x/6=180

x=180*6/9

x=20*6

x=120

therefore

A= x/2-x/3=120/2-120/3=60-40=20

B=x/3=120/3=40

C=x=120

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Step-by-step explanation:

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