Question

In triangle ABC; angleA = 60°, angleC = 40° and
bisector of angle ABC meets side AC at point
P. Show that BP = CP.​

Answer 1

Answer:

angle A =60°,angleC=40°so angleB=80°

the bisector of angleABC is equal to 40°

since here, angle PBC =anglePCB

therefore by using property that if in a triangle two angles are equal then there corresponding lines are also equal

so, BP=CP.

Answer 2

Step-by-step explanation:

this question csn not be done as BP at no rate can be equal to CP