Question

in triangle abc angleA=angleB/2=angleC/2 then find angleA​

Answer 1

Answer:

Let angle A = x

Angle B = y

As mentioned in the question angle C = 3 angle B = 3y

Angle C is also given as 2(Angle A + Angle B)

= 2(x+y)

So,

3y = 2(x+y)

y = 2x

So angle C = 3y = 6x

We know that sum of all the 3 angles in a triangle = 180deg

Therefore,

Angle A+ Angle B + Angle C = 180

x+ 2x+ 6x = 180

x = 20

Hence Angle A = 20

Angle B = 40

Angle C = 120