In triangle ABC,angleB is 90 and BD is perpendicular on AC then prove that triangleADB is similar to triangleBDC
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Step-by-step explanation:
Given:
<ABC= 90°
BD is perpendicular to AC
To Prove:
∆ADB is similar to ∆BDC
Proof:
BD = BD. given
AD = AC. given
therefore ∆ABD is similar to ∆BDC AA rule
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