Math, asked by sujitsingh7667, 10 months ago

In triangle ABC,angleB is 90 and BD is perpendicular on AC then prove that triangleADB is similar to triangleBDC

Answers

Answered by itsutsab
1

Step-by-step explanation:

Given:

<ABC= 90°

BD is perpendicular to AC

To Prove:

∆ADB is similar to ∆BDC

Proof:

BD = BD. given

AD = AC. given

therefore ∆ABD is similar to ∆BDC AA rule

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