in triangle ABC, BC=5,AC=4 and cos (a-b)=7/8 find value of 96cos c
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Answer:
We have, AB = 4 and BC = 3.
By Pythagoras theorem, we have
AC
2
=AB
2
+BC
2
⇒AC=
AB
2
+BC
2
⇒AC=
4
2
+3
2
=
25
=5
When we consider the t-ratios of ∠A, we have
Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.
∴sinA=
AC
BC
=
5
3
,cosA=
AC
AB
=
5
4
,tanA=
AB
BC
=
4
3
solution
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