In triangle ABC, BC-AB and angle B is 80 degree then find angle A
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IN ABC
BC=AB ..(
(ABC IS ISOSCELES )
<B=<C= 80• (ANGLES OPPOSITE TO CONGRUENT SIDES)
<A+ANGLE B + <C= 180
80+80+C=180•..(MEASURE OF ALL ANGLES OF TRIQNGLE IS 180)
160+A=180
A=180-160
A=20•
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