In triangle abc BC is produced to D if angle ACD is 110 degree and angle abc is 70 degree find angle BAC
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Acb=180-acd(110)=70
Bac=180-abc(70)-acb(70)=40
Bac=40
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Given : triangle abc, bc is produced to d,
∠acd = 110°
ab = ac
To Find : ∠a
Solution:
∠acd = 110°
∠c + ∠acd = 180° Linear Pair
=> ∠c + 110° = 180°
=> ∠c = 70°
ab = ac
=> ∠b = ∠c
=> ∠b = 70°
in Δabc
∠a + ∠b + ∠c = 180°
=> ∠a + 70° + 70° = 180°
=> ∠a + 140° = 180°
=> ∠a = 40°
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