in Triangle ABC BD is the altitude to side AC. If BD exceed AC by 5cm then area is 12 sq cm. Find AC and BD
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Answer:
Step-by-step explanation:
Since 5
2
+12
2
=13
2
, the triangle is a right angled triangle with base BC=5cm, and height AC=12cm
Area of triangle =
2
1
× base × height =
2
1
×5×12=30 sq cm
Area of triangle remains same, if we consider any of the base and its corresponding height to calculate it.
So, if the altitude drawn from B to AC is BD, then
2
1
×12×BD=30 sq cm
∴BD=5cm
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