In triangle abc , bdis perpendicular to ac , ce is perpendicular to ab , if bd
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In triangle ABC BD is perpendicular to AC
In triangle ABC BD is perpendicular to AC and CE is perpendicular to AB . if BD and CE intersect at o, prove that angle BOC=180-angle A.
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Step-by-step explanation:
Given:
In ∆abc:
line bd=perpendicular to line ac
line ce= perpendicular to line ab
therefore,
the sum of the internal angles of a triangle is equal to 180°
line bd intersect line ce at point O
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