Question

in triangle ABC, BE is perpendicular to AC, AD is any line drawn from A to BC intersecting BE in M. X,Y and Z are respectively the mid-points of AM, AB and BC. Prove that angle XYZ=90 degree 

Answer 1

in triangle ABM y & x are mid points of AM &AB so yx is parallel to BM (MID POINT THEOREM) also in triangle ABC Y & Z are the mid points of AB & BC so YZ parallel AC (MID POINT THEOREM) there for angle XYZ = 90 degree