in triangle abc bf is the altitude to ac and ae is the altitude to bc.if ac=45cm bc=15cm and abc=225cmsquare find bf and ae
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IF, BF IS ALTITUDE OF AC.
AC CAN BE TELL AS BASE OF TRIANGLE.
AREA OF TRIANGLE
=½*BASE*ALTITUDE=225CM²
=½*45*ALTITUDE=225CM²
45*ALTITUDE=225*2
ALTITUDE=450/45
AE=10CM
IF, AE IS ALTITUDE OF BC.
BC CAN BE KNOWN AS BASE OF TRIANGLE .
AREA OF TRIANGLE =
½*BASE*ALTUTUDE=225CM²
=½*15*ALTITUDE=225CM²
15*ALTITUDE=225*2
ALTITUDE =450/15
AE=30CM
AC CAN BE TELL AS BASE OF TRIANGLE.
AREA OF TRIANGLE
=½*BASE*ALTITUDE=225CM²
=½*45*ALTITUDE=225CM²
45*ALTITUDE=225*2
ALTITUDE=450/45
AE=10CM
IF, AE IS ALTITUDE OF BC.
BC CAN BE KNOWN AS BASE OF TRIANGLE .
AREA OF TRIANGLE =
½*BASE*ALTUTUDE=225CM²
=½*15*ALTITUDE=225CM²
15*ALTITUDE=225*2
ALTITUDE =450/15
AE=30CM
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