in triangle ABC cosC +cosA/c+a +cosB/b =
Answers
Answered by
0
Answer:
L.H.S =
c+a
cosC+cosA
+
b
cosB
=
b(c+a)
bcosC+bcosA+(c+a)cosB
=
b(c+a)
(bcosC+ccosB)+(bcosA+acosB)
=
b(c+a)
a+c
=
b
1
= R.H.S. Hence proved.
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