In triangle ABC; D and E are mid-points of the
sides AB and AC respectively. Through E, a
straight line is drawn parallel to AB to meet
BC at F. Prove that BDEF is a parallelogram.
If AB=16 cm, AC=12 cm and BC=18 cm, find the perimeter of the parallelogram.
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Given: D and F are mid points of AB and AC respectively.
Hence, by mid point theorem, DF∥BC
Also, given BD∥EF
Since, opposite sides are parallel to each other. Hence, BDEF is a parallelogram
Perimeter of BDEF = 2(BD+BE) (opposite sides of parallelogram are equal)
Perimeter of BDEF = AB+BC (D and E are mid points of AB and BC respectively)
Perimeter of BDEF = 16+18
Perimeter of BDEF = 34 cm
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